Math can be managed without English proficiency.

I used to be a math teacher at a secondary high school so I will give you a problem relating a diagram. (grade 6 level in Japan but a bit harder)

Why don’t you try this graphic problem ?

Calculate the area of the shaded triangle AEB.
Given : ABCD is rectangle, BC=6cm, CE=2cm, ∠AEB=45゜

Easy or hard ?

Solution to the above problem.

First of all, since angle AEB is 45 degrees, side EA is extended to form a right-angled isosceles triangle FBE below.

Extend the side CB 2 cm to the left and set point G. Connect point F and point G. FGCE is a trapezoid.

∠EBC ＋ ∠FBE ＋ ∠FBG = 180°　∠FBE is a right angle ,∠EBC ＋ ∠FBG = 90°hence ∠BFG = ∠EBC. Side FB = side BE

Triangle FBG and BEC are congruent (SAS)

The area of the trapezoid FGCE is 32㎠　( 6＋2 ) × 8 ÷ 2 = 32

The area of the triangle FBG and BEC are 6㎠ each　6 × 2 ÷ 2 = 6

Hence the area of the triangle FBE is 20㎠

FA and AE have lengths in a ratio of 1:3 since segment BC is 6cm and segment GB is 2cm.

Hence FBA and ABE have areas in a ration of 1:3

Area of triangle AEB = 15㎠　　20× 3/4 = 15

Mathematics helps to develop logical and critical thinking and provides tools for understanding science, engineering , and technology.